25x^2-70x+40=0

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Solution for 25x^2-70x+40=0 equation: 



25x^2-70x+40=0

a = 25; b = -70; c = +40;
Δ = b2-4ac
Δ = -702-4·25·40
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-30}{2*25}=\frac{40}{50}
=4/5
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+30}{2*25}=\frac{100}{50}
=2
$

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